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2-7n^2=-49
We move all terms to the left:
2-7n^2-(-49)=0
We add all the numbers together, and all the variables
-7n^2+51=0
a = -7; b = 0; c = +51;
Δ = b2-4ac
Δ = 02-4·(-7)·51
Δ = 1428
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1428}=\sqrt{4*357}=\sqrt{4}*\sqrt{357}=2\sqrt{357}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{357}}{2*-7}=\frac{0-2\sqrt{357}}{-14} =-\frac{2\sqrt{357}}{-14} =-\frac{\sqrt{357}}{-7} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{357}}{2*-7}=\frac{0+2\sqrt{357}}{-14} =\frac{2\sqrt{357}}{-14} =\frac{\sqrt{357}}{-7} $
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